226.E 翻转二叉树
Problem: 226. 翻转二叉树
思路
递归法。先递归翻转左右子树,然后交换根节点的左右子树。
Code
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func invertTree(root *TreeNode) *TreeNode {
if root == nil {
return root
}
left := invertTree(root.Left)
right := invertTree(root.Right)
root.Left = right
root.Right = left
return root
}
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